Tricks
Let principal =P
Rate =R%
Time=n years
1.If interest is compounded annually, then
Amount=P(1+R/100)^n
Compound Interest= Amount –Principal
Compound Interest= P[(1+R/100)^n - 1]
2.If the interest is compounded half-yearly ,then R=R/2 & n=2n then
Amount=P(1+R/2 × 100)^2n
3.If the interest is compounded quaterly, then R=R/4 & n=4n
then Amount=P(1+R/4 × 100)^4n
4. If interest is compounded (1+{(a/b)R }/ 100)
5.If rates of interest are R1%, R2% and R3% for 1st,2nd and 3rd year respectively,then
Amount=P(1+R1/100) (1+R2/100)( 1+R3/100)
Q. Find the compound interest on Rs 8000 at 4% p.a for 2yrs compounded annually.
Solution: Given that P=Rs 8000
R=4%
Time= 2year
Now according to the formula,
Amount= P(1+R/100)^n
= 8000(1+4/100)^2
=8000 x 26/25 x 26/25
=Rs. 8652.80
Therefore, CI=Amount – principal
=Rs.8652.80 – Rs. 8000
=Rs.652.80
Q. Ruchi invested Rs. 1600 at the rate of compound interest for 2 years. She got Rs. 1764 after the specific period. Find the rate of interest
Solution : Given that P=Rs 1600
Time= 2year
Amount= Rs 1764
Now according to the formula,
Amount= P(1+R/100)^n
1764=1600(1+R/100)^2
1760/1600 = (100+R/100)^2
441/400 = (100+R/100)^2
(21/20)^2=(100+R/100)^2
100+R/100 = 21/20
100 + R=21/20 X 100
100 + R= 105
R= 105 – 100=5%
Q. Find the compound interest on Rs5000 in 2years at 4%, if the interest being compounded half-yearly.
Solution: Given that P = Rs 5000
R=4%
Time= 2year
Now according to the formula,
Amount= P(1+R/2 x 100)^2n
= 5000(1+4/100)^4
=5000 x 51/50 x 51/50 x 51/50 x 51/50
=51 x 51 x 51 x 51 / 1250
=Rs. 5412.16
Therefore, CI=Amount – principal
=Rs.5412.16 – Rs. 5000
=Rs.412.16
Q. Find the compound interest on Rs8000 in 9months at 20%, if the interest being compounded quarterly.
Solution: Given that P = Rs 8000
R=20%
Time= 9 months = ¾ year
Now according to the formula,
Amount= P(1+R/4 x 100)^4n
= 8000(1+20/400)^(3/4 x4)
= 8000(1+5/100)^3
=8000 x 21/20 x 21/20 x 21/20
=Rs. 9261
Therefore, CI=Amount – principal
=Rs.9261 – Rs. 8000
=Rs.1261
Tricks of True Discount and Banker's Discount
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