Q. Average weight of 20 girls in a class is 25 kg, when the age of a teacher is included the average weight increased by 2 then find out the weight of the teacher.
Answer 67
EXPLANATION
It is given that average weight of 20 girls is 25 kg,
let the teacher’s weight is X kg
25 = sum of the weights of 20 girls / 20
sum of the weights of 20 girls = 500
25 + 2 = (500 + X) /21
X = 67 kg
Q. If Aman borrowed same amount from Babu as Babu from Arun at the same rate of interest for 3 Years at simple interest while Babu borrowed at compound interest compounded annually at same rate and time period and the difference Between their interest is Rs. 992.25 then find the Rate pcpa if Aman borrowed Rs. 14,000.
Answer
EXPLANATION
992.25 = 14000 (r/100 )^2 (300+r/100 )
567/8 = r^2 (300+r/1000 )
Or, 70875 = r^2 (300 + r)
By moving through options we find that r = 15 % will satify the above equation.
Q. 3 men and 7 women can complete a piece of work in 12 days. 7 men and 3 women can complete the same work in 8 days. In how many days can 3 women complete the work alone?
Answer
EXPLANATION
In time work we all know that, more man power means less time.
M= men
W= women
3m + 7w = 12 ----(i)
7m + 3w = 8 ------(ii)
The two equations will be equal after some manipulations.
1/4 (3m + 7w) = 48 = 1/6 (7m + 3w)
=> 18m + 42w = 28m + 12w
=> 10m = 30w
=> 1m = 3w
Now putting this into equation (i),
3*3w + 7w = 12
=> 16w = 12
=> 1w = 192
Therefore, 3 women will take = 192/3 = 64 days
SBI questions with answer set 3
Q. A train reaches on a destination in time with an average speed of 40 Kmph. If it goes with an average speed of 35 Kmph it is late by 15 minutes. The length of the total journey is
Answer 70 km
EXPLANATION
The trains need to travel 15 min. extra @ 35 Kmph so it is behind by 8.75 Km .
Rate of losing distance is 5 Kmph hence the train must be travelled for 8.75/5=1 Hour 45 minutes @ 40 kmph ⟶ 70 Km
Alternative Approach: Since distance is constant, therefore
s1/s2=t2/t1
40/35=t-15/t where t is time taken to reach on time.
t=105 min = 105/60 hours
Total distance = s1*t1 = 40*105/60 = 70km
Q. Two pipes X and Y can fill a cistern in 24 minutes and 32 minutes respectively. If both the pipes are opened together, then after how much time (in minutes) should Y be closed so that the tank is full in 18 minutes?
Answer
EXPLANATION
Rate of filling a cistern with pipe X = 1/24
Rate of filling a cistern with pipe Y = 1/32
Given: If both the pipes are opened together and after some time pipe Y has closed.
Let pipe Y is closed after x minutes.
Therefore part of cistern filled with pipes X and Y
18/24 + x/32 = 1
1/4 = x/32 ⇒ x = 8 minutes
Q. The ratio between the ages of a father and a son at present is 5 : 2, respectively. Four years hence, the ratio between the ages of the son and his mother will be 1 : 2, respectively. What is the ratio between the present ages of the father and the mother respectively?
EXPLANATION
suppose the ages of father and son are 5x yr and 2x yr After four years, the age of son = (2x + 4) yr
After four years, the age of mother = (4x + 8) yr
So, the present age of mother = (4x + 4) yr
Ratio of the age of father and mother =5x : 4x + 4
Since, data is insufficient, so cannot be determined.
Q. The daily work of 2 men is equal to that of 3 women or that of 4 youngsters. By employing 14 men, 12 women and 12 youngsters a certain work can be finished in 24 days. If it is required to finish it in 14 days and as an additional labour, only men are available, how many of them will be required?
Answer
EXPLANATION
let, men = M, women = W , Youngster = Y
Then 2M = 3W = 4Y
W = 2/3 M and Y = 1/2 M
Given 14M + 12W + 12Y
14 + 2/3 × 12 + 1/2 × 12
28 men
28 × 24 = m × 14 = m = 48
Therefore, additional labour = 48 – 28 = 20
Q. Two trains A and B leave stations P and simultaneously and travel towards Q and P respectively on the same route. After meeting en route, A takes one hour to reach Q and B takes 4 hours to reach P.How long did A take to cover the entire Distance?
Answer
EXPLANATION
A takes 1 hour after meeting and B takes 4 hours after meeting. Hence Time traveled before meeting = v1.4 = 2 hours Time taken by A= 2+1 = 3 hours
Answer 67
EXPLANATION
It is given that average weight of 20 girls is 25 kg,
let the teacher’s weight is X kg
25 = sum of the weights of 20 girls / 20
sum of the weights of 20 girls = 500
25 + 2 = (500 + X) /21
X = 67 kg
Q. If Aman borrowed same amount from Babu as Babu from Arun at the same rate of interest for 3 Years at simple interest while Babu borrowed at compound interest compounded annually at same rate and time period and the difference Between their interest is Rs. 992.25 then find the Rate pcpa if Aman borrowed Rs. 14,000.
Answer
EXPLANATION
992.25 = 14000 (r/100 )^2 (300+r/100 )
567/8 = r^2 (300+r/1000 )
Or, 70875 = r^2 (300 + r)
By moving through options we find that r = 15 % will satify the above equation.
Q. 3 men and 7 women can complete a piece of work in 12 days. 7 men and 3 women can complete the same work in 8 days. In how many days can 3 women complete the work alone?
Answer
EXPLANATION
In time work we all know that, more man power means less time.
M= men
W= women
3m + 7w = 12 ----(i)
7m + 3w = 8 ------(ii)
The two equations will be equal after some manipulations.
1/4 (3m + 7w) = 48 = 1/6 (7m + 3w)
=> 18m + 42w = 28m + 12w
=> 10m = 30w
=> 1m = 3w
Now putting this into equation (i),
3*3w + 7w = 12
=> 16w = 12
=> 1w = 192
Therefore, 3 women will take = 192/3 = 64 days
SBI questions with answer set 3
Q. A train reaches on a destination in time with an average speed of 40 Kmph. If it goes with an average speed of 35 Kmph it is late by 15 minutes. The length of the total journey is
Answer 70 km
EXPLANATION
The trains need to travel 15 min. extra @ 35 Kmph so it is behind by 8.75 Km .
Rate of losing distance is 5 Kmph hence the train must be travelled for 8.75/5=1 Hour 45 minutes @ 40 kmph ⟶ 70 Km
Alternative Approach: Since distance is constant, therefore
s1/s2=t2/t1
40/35=t-15/t where t is time taken to reach on time.
t=105 min = 105/60 hours
Total distance = s1*t1 = 40*105/60 = 70km
Q. Two pipes X and Y can fill a cistern in 24 minutes and 32 minutes respectively. If both the pipes are opened together, then after how much time (in minutes) should Y be closed so that the tank is full in 18 minutes?
Answer
EXPLANATION
Rate of filling a cistern with pipe X = 1/24
Rate of filling a cistern with pipe Y = 1/32
Given: If both the pipes are opened together and after some time pipe Y has closed.
Let pipe Y is closed after x minutes.
Therefore part of cistern filled with pipes X and Y
18/24 + x/32 = 1
1/4 = x/32 ⇒ x = 8 minutes
Q. The ratio between the ages of a father and a son at present is 5 : 2, respectively. Four years hence, the ratio between the ages of the son and his mother will be 1 : 2, respectively. What is the ratio between the present ages of the father and the mother respectively?
EXPLANATION
suppose the ages of father and son are 5x yr and 2x yr After four years, the age of son = (2x + 4) yr
After four years, the age of mother = (4x + 8) yr
So, the present age of mother = (4x + 4) yr
Ratio of the age of father and mother =5x : 4x + 4
Since, data is insufficient, so cannot be determined.
Q. The daily work of 2 men is equal to that of 3 women or that of 4 youngsters. By employing 14 men, 12 women and 12 youngsters a certain work can be finished in 24 days. If it is required to finish it in 14 days and as an additional labour, only men are available, how many of them will be required?
Answer
EXPLANATION
let, men = M, women = W , Youngster = Y
Then 2M = 3W = 4Y
W = 2/3 M and Y = 1/2 M
Given 14M + 12W + 12Y
14 + 2/3 × 12 + 1/2 × 12
28 men
28 × 24 = m × 14 = m = 48
Therefore, additional labour = 48 – 28 = 20
Q. Two trains A and B leave stations P and simultaneously and travel towards Q and P respectively on the same route. After meeting en route, A takes one hour to reach Q and B takes 4 hours to reach P.How long did A take to cover the entire Distance?
Answer
EXPLANATION
A takes 1 hour after meeting and B takes 4 hours after meeting. Hence Time traveled before meeting = v1.4 = 2 hours Time taken by A= 2+1 = 3 hours
