Tricks....
1. Single discount equivalent to two successive discounts x% and y%
= ( x + y - xy / 100)%
2. If a shopkeeper wants a profit of R% after allowing a discount of r%, then Marked Price(MP) of the item
= CP{(100+R)/(100-r)}
3. If a shopkeeper allows a discount of y% on an article and marked price of the article is x% more than the cost price, then profit or loss per cent in this transaction
= {x ×( 100- y) / 100} - y
Note: Positive value shows a profit, while negative value shows loss.
Q. What will be a single equivalent discount for successive discounts of 10% and 5% on marked price of an article?
EXPLANATION Given x = 10%, y = 5%
Single equivalent discount = ( x + y - xy / 100)%
= ( 10 + 5 - 10 × 5 / 100)%
= 14.5 %
Q. The marked price of a bicycle is 1100. A shopkeeper allows a discount of 10% and get a profit of 10%. Find the cost price of the bicycle.
EXPLANATION
Here MP = 1100, r = 10%, R = 10%
According to the question,
CP = MP {( 100 - r) /(100+R)}
= 1100 {(100- 10)/(100+10)}
= 1100 { 90/110}
= 900
Q. A shopkeeper marked the price 10% more than its cost price. If he allows a discount of 20%, then find his loss per cent.
EXPLANATION
Here x = 10%, y = 20%
According to the question,
Loss or profit per cent ={ 10 ×(100-20) / 100} - 20
= 10× 80 / 100 - 20
= 8 - 20
= - 12
Therefore loss per cent = 12%
Q. If on a marked price, the difference of selling prices with a discount of 30% and two successive discounts of 20% and 10% is X 72, then find the marked price (in X).
EXPLANATION
Let the marked price = x
The discount equivalent to successive discounts 20% and 10% = (x + y - xy/100)%
where x = 20, y = 10
Then 30 - 2 = 28%
According to the question
{(100- 28)x/100} - {(100-30)x/100} = 72
x = 72 × 100 / 2 = 3600
Q. On a 20% discount sale, an article costs 596. What was the original price of the article?
EXPLANATION
Let the original price be x
At 20% discount,an article costs 596
Therefore
596 = 80/ 100 × x
x = 745
Therefore original price = 745
Tricks of Average
Tricks of Percentage
Tricks of Divisibility
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