Tricks of Age Questions

 Tricks

1. If present age of the father is F times the age of his son. T years hence, the father's age become Z times the age of son then present age of his son is given by [(Z - 1)T / (F - Z)]

Q. Present age of the father is 9 times the age of his son. One year later father's age become 7 times of his son. What are the present ages of the father and his son.

                a) 27              b) 30

              c) 36              d) 43

Solution 

Son's age = [( 7- 1) ×1] / [9 - 7]

                  = 6 / 2

                  = 3

So father's age = 9 × son's age

                            = 9 × 3

                            = 27 years

2. If T years earlier the age of the father was n times the age of his son, t years hence the age of the father becomes m times the age of his son then his son's age is given by

Son's age = [T ( n - 1) + t ( m - 1)] / ( n - m)

Q. 10 years ago Ravi's mother was 4 times older than her. After 10 years the mother will be twice older than the daughter. What is the present age of Ravi?

                 a) 16              b) 20

               c) 21              d) 35

Solution 

Ravi's age = [ 10 ( 4- 1) + 10 ( 2 - 1)] / ( 4 - 2)

                   = 20

3. Present age of Father : Son = a : b

After/ before T years = m : n

Then Son's age = b × [ T (m - n) / ( an - bm)] 

and father's age = a ×[T (m - n) / (an - bm)] 

Q. The ratio of the ages of the father and the son at present is 3 : 1, four years earlier, the ratio was 4 : 1. What are the present ages of the son and the father? 

Solution

Ratio of present age of father and son = 3 : 1

4 years before = 4 : 1

Son's age = 1× [ 4 ( 4- 1) / ( 4×1 - 3×1)]

                 = 12

Father's age = 3 × [ 4 (4 - 1) / (4×1 - 3×1)]

                       = 36

Shortcut tricks of Work and Wages

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এই ফেচবুক ষ্টেটাছ তোমাৰ বাবে......

 

বিদ্যা শপত খাই কৈছো, কাকো পাহৰা নাই মই। কাৰোবাক কন্দুৱাবলৈ ইচ্ছাও নাই মোৰ। ভগৱানৰ ওচৰত বিচাৰিছোঁ - যাক মই মনত পেলাওঁ, তেওঁ যাতে এনেদৰে মোক মনত পেলায়। যদিও মই জানো, সম্পৰ্ক গঢ়াটো চক পেঞ্চিলেৰে ব্লেক ব'ৰ্ডত লিখাৰ নিচিনা অাৰু সম্পৰ্ক বজাই ৰখাটো বৈ থকা পানীত পানীৰে লিখাৰ নিচিনা। হয়, নামেই নহয়। মানুহে অবয়ৱ-চেহেৰা পাহৰি যায়। সাগৰত নহয়, বহু সময়ত মানুহে চকুৰ নদীতে ডুব যায়। বিদ্যা শপত খাই কৈছোঁ - - মোৰ চকুৰ নদীত কোনেও ডুব যোৱা নাই, সকলোৱে এই নদীত সাঁতুৰিয়ে আছে। 

শিলক এনেদৰে পূজা কৰিব নালাগে যে এই শিল দেৱতা হৈ পৰে। কাকো এনেদৰে ভাল পাব নালাগে যে প্ৰবঞ্চক হৈ পৰে। চকুৰ শব্দ অন্য। চকুপানীৰ জুই অন্য। কোনেনো বিচাৰে আপোন গৰাকীৰ পৰা বিচ্ছেদ। আচলতে ভাগ্যৰ কথাই বেলেগ এক অন্য। 

প্ৰেমে দিয়া আঘাত কাকো দেখুৱাব নালাগে, কাৰণ অইনৰ হাতৰ মুঠিত থাকে যে নিমখ। বিচ্ছেদৰ ভাষাৰে নিজক নিচুকাব নালাগে, কাৰণ তেতিয়া জীবন হৈ পৰে নিৰস। 

তোমাৰ ওচৰলৈ আহিৱ নোৱাৰিলোঁ মই - - আবেলিৰ চৰাই জাকৰ সৈতে। তোমাৰ ওচৰলৈ আহিৱ নোৱাৰিলোঁ মই শীতৰ ৰ'দজাকৰ দৰে। মই হব নোৱাৰিলোঁ তোমাৰ বসন্তৰ কুলি। কব নোৱাৰিলোঁ বহু কথা খুলি। হয়, দিন গল গলি গলি। সেয়ে অৱশ্যে চিয়াঁহিৰে মই লিখোঁ জীবন যৌৱনৰ চকুলো। 

বিদ্যা শপত খাই কৈছোঁ--- সাগৰৰ পানী মিঠা নোহোৱালৈকে কাকো নাপাহৰোঁ। নৈ হৈ বৈ থাকিম। নিৰৱধি। হয়, কাকো পাহৰা নাই মই। ভগৱানৰ ওচৰত বিচাৰিছোঁ, 'যাক মই মনত পেলাওঁ, তেওঁ যাতে মোক এনেদৰে মনত পেলায়'। 

বৰ্ষাৰণ্য আপুনি কিয় চোৱা উচিত? 

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'বৰ্ষাৰণ্য' আপুনি কিয় চোৱা উচিত ?

প্ৰকৃতিপ্ৰেমীৰ বাবে এখন অসমীয়া চলচ্চিত্ৰ 'বৰ্ষাৰণ্য'

১)বৰ্তমান সময়ত আপুনি বাতৰি কাকত অথবা টেলিভিছন চেনেলৰ দ্বাৰা বন বিভাগৰ নগ্ন স্বৰূপ সংক্ষিপ্ত বাতৰি আকাৰে পাই আহিছিল। বৰ্ষাৰণ্য'ত ইয়াক বিস্তৃত ৰূপত দেখিবলৈ পাব। 

২)কিছুমান বিলুপ্তপ্ৰায়ী প্ৰাণীয়েই হওক বা কেৱল বৰ্ষাৰণ্যত উপলব্ধ হোৱা 'জুৱেল' অৰ্কিডেই হওক, প্ৰকৃতিৰ বিষয়ে কিছুমান নজনা কথা জানিব পাৰিব। বিশেষকৈ শিক্ষাৰ্থী সকলে বৰ্ষাৰণ্যৰ সৃষ্টি, গঠন আদিৰ বিষয়ে জনাত সুবিধা হব। 

৩) ছবিখন চোৱাৰ পাছত ক্ৰমাৎ বৃদ্ধি পাবলৈ ধৰা বনধ্বংস ৰোধ কৰিবলৈ আপুনিও আগবাঢ়ি আহিবলৈ বাধ্য হব। সামগ্ৰিক ভাৱে প্ৰকৃতিপ্ৰেমীৰ বাবে বৰ্ষাৰণ্য উৎকৃষ্ট ছবি। 

Tricks of VARIATION and PARTNERSHIP 

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Tricks of VARIATION AND PARTNERSHIP

Shortcut Tricks of Partnership

1. Two numbers are in the ratio a : b. If p is added to the first number and q is added to the second number respectively, then ratio of the resulting numbers become    m : n. Then 

the original first number

                    = [ a (mq - np) ] / (an - bm) 

the original second number 

                    =[ b (mq - np)] / (an - bm) 

Q. In the class, the number of boys and girls is in the ratio of 4 : 5. If 10 more boys join the category, the ratio of numbers of boys and girls becomes 6 : 5. How many girls are there in the class? 

              a) 20               b) 30

             c) 25                d) Couldn't be determined 

Solution : c)

Number of girls = [b (mq - np)] / (an - bm) 

                              = [5 ( 6 ×0 - 5× 10)]/ ( 4×5 - 5×6) 

                              = 25

2. If on adding x to four numbers a, b, c, d; the resulting numbers become proportional then

         x = (bc - ad) / [(a + d) - (b + c)] 

Q. What must be deducted from each of the numbers 7,10,12 and 18 so that the resultant numbers are in proportion? 

               a) 1              b) 2

               c) 3              d) 4

Solution : b) 

Required number = (bc - ad) / [ (a + d) - ((b + c)] 

                     = ( 10×12 - 7 ×18) / [( 7 + 18) - ( 10 + 12)]

                     = - 6/3

                     = - 2

Thus 2 must be subtracted from each of the numbers. 

3. The ratio between two numbers is a : b, if each number is increased by x, the ratio becomes c : d. 

Then sum of two numbers 

                 = [x (a + b) (c - d)] /(ad - bc) 

Q. Two numbers are within the ratio 2 : 3. If 4 be added to both of them, then their ratio becomes 3 : 4. Find the sum of the numbers 

               a) 10             b) 15

              c) 20              d) 25

Solution : b) 

Sum of two numbers = [ 4 (a +b) (c - d)] /(ad - bc) 

                     = [ 4 (2 + 3) ( 3 - 4)] / (2×4 - 3×3)

                     = 20

COMPUTER AWARENESS

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Problems on Work and Wages

Problems on Work and Wages with explanation

Q. A can do a piece of work in 3 days while B can do the same work in 4 days. If they work together for a total wages of 2800, how much does A get? [Bank Clerks 2009]
Solution
A's 1 day's work = 1/ 3
B's 1 day's work = 1 /4
A's share : B's share
   = 1 / 3 : 1 / 4
   = 4 : 3
A's share = 4/7 × 2800
                = 1600

Q. A alone can do a piece of work in 3 days, while B alone can do the same work in 2 days. If they work together to complete the work, their total wages is fixed 225. Find the share of A. [RRB 2008]
Solution
A's 1 day's work = 1 / 3
B's 1 day's work = 1 / 2
A's share : B's share = 1 / 3 : 1 / 2
                                 = 2 : 3
Share of A = 2 / 5 × 225
                  = 90


Q. A alone can finish a work in 2 days, while B alone can finish it in 3 days. If they work together to finish it, then out of total wages of 6000, what will be the 20% of A's share? [Hotel Mgmt. 2009]
Solution
A's 1 day's work = 1/ 2
B's 1 day's work = 1 /2
A's share :B's share = 1 / 2 : 1 / 3
                       = 3 : 2
Therefore
A's share = (3 / 5) × 6000
                = 3600
Therefore 20% of A's share = 3600 × 20 / 100
                                    = 720
Q. Vandana can do a piece of work in 10 days. With the help of Ruchi, she can do the same work in 6 days. If they get 200 for that work, then what will be the share of Ruchi in the received remuneration?
Solution
Vandana's 1 day work = 1/10
( Vandana + Ruchi)'s 1 day's work = 1 / 6
Therefore Ruchi' s 1 day's work = 1/ 6 - 1/10
                                 = 4/60 = 1/15
Ratio of wages of Vandana and Ruchi
                     = 15 : 10
Ruchi's wages ={A /( A + B)} × total wages
                        = (10 / 25) × 200
                        = 80

Q. A sum of money is sufficient to pay A's wages for 21 days and B's wages for 28 days. The same money is sufficient to pay the wages of both for [SSC CCL 2013]
Solution
A's 1 day's work = 1 / 21
B's 1 day's work = 1 / 28
Therefore same money is sufficient to pay the wages of both for = 1 / { (1/21) + (1/28)}
     = (21 × 28)/ 49
     = 3× 4
     = 12 days

Shortcut tricks of Work and Wages

Shortcut tricks of Time and Work problem 

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Shortcut tricks on WORK AND WAGES

Fast Track Formulae to solve the QUESTIONS on Work and Wages

1.If A and B can do a piece of work in x and y days respectively, the ratio of their wages will be y: x. Then, the wages earned by A and B will be
    A's wages = {Total wages /(x + y)} × y
    B's wages = { Total wages / ( x + y)} × x

Q.Akansha can do a piece of work in 6 days, while Vasudha can do the same work in 5 days. If the total amount to be given for this work is 660, then what will be the share of Vasudha, if both work together.
Solution
Time taken by Akansha = 6 days
Therefore 1 days work = 1 / 6
 And
Time taken by Vasudha = 5 days
Therefore 1 days work = 1 / 5

Total amount earned = 660
Ratio of their incomes = 1 / 5 : 1 / 5 = 5 : 6
Therefore
 Vasudha's share ={660 / (5 + 6)} × 6
                            = 360

2. A can do a piece of work in x days. With the help of B, A can do the same work in y days. If they get a for that work, then
Share of A = ay / x
Share of B = a ( x - y) / x

Q. Suresh can do a work in 20 days. Suresh and Surendra together do the same work in 15 days. If they got 400 for that work, then find the share of Suresh and Surendra?
Solution
Here x = 20, y = 15, a = 400
Now, according to the formula
Share of Suresh = ay / x
                           = 400 × 15 / 20
                           = 300
Share of Surendra = a ( x - y) / x
                            = 400 ( 20 - 15) / 20
                            = 100


3. X, Y and Z undertake to do a work for R. If together they do only m/n of the work and rest is done by C alone, then the share of C is given by
                R ( 1 - m / n)

Q. A, B and C undertake to do a work for 480. A and B together do 1/4 of the work and rest is done by the C alone. How much should C get?
Solution
Here R = 480, m = 1, n = 4
Now according to the formula
Share of C = R ( 1 - m / n)
                  = 480 ( 1 - 1 / 4)
                  = 360

Q. Shantanu can do a piece of work in 12 days and Manu can do the same work in 10 days. If they work together, in what ratio Shantanu and Manu will receive their wages?
Solution
Shantanu's 1 day's work = 1 / 12
Manu's 1 day's work = 1/10
Shantanu's share : Manu's share
        = 1/12 : 1/10
        = 10 : 12
        = 5 : 6

Q. A alone can do a piece of work in 8 days while B alone can do it in 10 days. If they together complete this work and get 900 as their remuneration, then find the shares of both the persons.
Solution
Ratio of wages of A and B = 10 : 8
A's wages = { A / (A + B)} × total wages
                 = {10 / (10 + 8)} × 900
                 = 500
Similarly
B's wages = { 8 / (10 + 8)} × 900
                 = 400

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Computer Awareness

Computer Awareness

1.To perform calculation on stored data computer uses…… number of system. [SBI CLERK 2009]
      A. Decimal. 
      B. Hexadecimal.
      C. Octal.     
      D. Binary
      E. None of these
Answer D. Binary

2.A hexadecimal number is represented by
      1. Three digits.
      2. Four binary digits.
      3. Fiur digits.
      4. All of these
      5. None of these
Answer 2. Four binary digits

3.What is the value of binary number 101?
      A.  3         B. 5
      C.  6         D. 101
Answer 2. 5

4.Which of the following is an example of binary number
      A. 6AH.
      B. 10100
      C. 005.
      D. G3Do
      E. All of these
Answer B. 10100

5.Which of the following is not a binary number?
      A. 001.           B. 1010
      C. 203.           D. 10010
Answer C. 203

6.How many values can be represented by a single byte?
      A. 4             B. 16
      C. 64.          D. 256
Answer D. 256

7.The binary equivalent of decimal number 98 is [IBPS CLERK 2012]
      A. 1110001           B. 1110100
      C. 1100010           D. 1111001
Answer C. 1100010

8.MSD refers as
          A. Most significant digit
          B. Many significant digit
          C. Multiple significant digit
          D. Most Significant Decimal
          E. None of these
Answer A. Most significant digit

9.Binary system is also called
       A. Base one system
       B. Base two system
       C. Base system
       D. Binary system
       E. None of these
Answer B. Base two system

10.The most widely used code that represents each character as a unique 8 bit code is
       A. ASCII
       B. UNICODE
       C. BCD
       D. EBCDIC
       E. None of these
Answer A. ASCII

11.What type of information system would be recognised by digital circuits?
        A. Hexadecimal system
        B. Binary system
        C. Both '1' and '2'
        D. Only roman system
Answer C. Both '1' & '2'

12.The negative numbers in the binary system can be represented by
     A. Sign magnitude
     B. 1's compliment
     C. 2's compliment
     D. All of these
     E. None of these
Answer D. All of these

Practice questions on Time and Work problem

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Shortcut tricks of Time and Work problem


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Practice questions on Time and Work problem

Practice questions on Time and Work problem

1.If the work done by 8 men and 4 boys in 1 day is 7 times the work done by 1 man and 1 boy, then compare the work done by 1 man and 1 boy in 1 day? [CDS 2013]
Solution
Here a = 8, b = 1, x = 4, y = 1, n = 7
Therefore
Work done by 1 man / work done by 2 boy
      = (ny - x) / ( a - nb)
      = ( 7 × 1 - 4) / ( 8 - 7× 1)
      = 3 / 1
   

2.If 14 men and 12 boys can finish work in 4 days, while 8 men and 16 boys can finish the same work in 5 days. Compare the 1 day work of 1 man and 1 boy.
Solution
Here a = 14, b = 12, x = 4, y = 5, c = 8, d = 16
One day work of 1 man / one day work of 1 boy
     = ( yd - xb) / ( xa - yc)
     = ( 5 × 16 - 4 × 12) / ( 4 × 14 - 5 × 8)
     = 32 / 16
     = 2 / 1

3.A stock of food is enough for 240 men for 48 days. How long will the same stock last for 160 men? [CDS 2012]
Solution
Given M1 = 240, D1 = 48,
          M2 = 160, D2 =?
  Therefore M1 D1= M2 D2
           240 × 48 = 160 × D2
           D2 = 240 × 48 / 160
                = 72

4.45 people take 18 days to dig a pond. If the pond would have to be dug in 15 days, then the number of people to be employed will be [CDS 2012]
Solution
Given M1 = 45, D1 = 18
           M2 =?, D2 = 15
Therefore M1 D1= M2 D2
             45 × 18 = M2 × 15
             M2 = 54

5.A certain number of men can do a piece of work in 80 days. If there were 10 men less, It could be finished in 20 days more. How many men are there in the starting?
Solution
Here a = 10, D =80, d = 20
Therefore number of men in starting
            = a (D + d) / d
            = 10 × ( 80 + 20)/ 20
            = 50

6.20 workers working for 5 h per day complete a work in 10 days. If 25 workers are employed to work 10 h per day, what is the time required to complete the work? [CDS 2013]
Solution
Here M1 = 20, M2 = 25, T1 = 5, T2 = 10, D1 = 10, D2 =?
Therefore M1× D1 × T1= M2× D2× T2
                20 × 10 × 5 = 25 × D2 × 10
                D2 = 4
Therefore D2 = 4 days

7.A contractor undertook to do a certain piece of work in 18 days. He employed certain number of men but 12 of them being absent from the very 1st day, the rest could finish the work in 30 days. Find the number of men originally employed.
Solution
Let the number of men at the beginning = x
Given M1 = x, M2 = x - 12, D1 = 18, D2 =30
According to the formula
       M1 D1 = M2 D2
       x × 18 = (x - 12) × 30
       2x = 60
         x = 30


Shortcut tricks of Time and Work problem 

Shortcut tricks of Unitary Method

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